Cyphersum

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Well first you have to simplify each term individually then put them all together. In my explanation I'm going to assume you already have a general idea of how simplifying complex roots works. If that's not the case you might want to look into that first and then come back to this. So right off the bat we know that 2*root2 cannot be simplified since 2 does not have any square factors, 3*root20 on the other hand can be simplified since 20 is 4*5 and 4 is a square number.

3*root20 3*root(4*5) 3(2*root5) 6*root5

Then we look at the next term root45. This can also be simplified since 45 can also be expressed as 9*5 and 9 is 3². So,

root45 root(9*5) 3*root5

And last but not least we look at root288. Now if your sharp you can just realize that 288 is 144*2 and 144 is 12². Unfortunately I'm not that good so I just did it gradually. You can just start with the smallest square number you know that you think might be a factor, factor it out then square it to bring it out of the root and then just keep simplifying until you can't simplify anymore. Since 288 has 4 as a factor we can start there.

root288 root(4*72) 2*root72 2*root(4*18) 2(2*root18) 4*root18 4*root(9*2) 4(3*root2) 12*root2

Now going back to the original expression we just replace each root with it's simplified form.

2*root2+3*root20-root45-root288 2*root2+6*root5-3*root5-12*root2

Then just combine like terms.

2*root2+6*root5-3*root5-12*root2 2*root2+3*root5-12*root2 3*root5-10*root2

and that would be the simplified form of that expression. Hope that helps and that it wasn't too long
Oct 31, 2013