darkestmoose

Ohhhhkkkkkk thank you so muchh!!!

Find the domain and range of the inverse. Express your answer in interval notation

To find the inverse:

x=2y-3

x+3=2y

(x+3)/2=y

so the inverse of x=2y-3 is y=(x+3)/2

since the graph for this is just a just a line some degrees above the horizontal, the domain and range would be

Domain: {x|xER}        Range: {y|yER}

someone(geno3141) has already answered this q here, u will find it if u search for the q in the google search bar.

I've copied and pasted geno3141 's answer here for now: 

Geometric sequences have a common ratio, r    (it's a multiplier)

We have:  16,  16r,  16r2 = 8,  16r3 

Since  16r2 = 8,  r2  =  ½   and  r  =  sqrt(2)/2

b  =  8· sqrt(2)/2  =  4·sqrt(2)