eggRick2011

THANK YOU SO MUCH

Sorry!!!

Let f(n) be a function that, given an integer n, returns an integer k, where k is the smallest possible integer such that k! is divisible by n. Given that n is a multiple of 15, what is the smallest value of n such that f(n) > 15? 

THANKS

draw a graph and find the x value of point d that makes the area of xyd 20

simplify 3^2 first to get 9

9 times 4.75 is 36 + 9 * 3/4 or 27/4 

so 9 times 4.75 is 42 3/4 or 171/4

then you multiply by pi.

the answer is 171/4\(\pi \)

Since you want the least average, then you want the most amount of small numbers

There has to be a 5.5 median so the list would have to  have one 5 and one 6.

so the list would be 1,2,3,4,5,6,7,8,9,10 since there cannot be reapeats

1+2+3+4+5+6+7+8+9+10 is 11* 5 since 1+10 is 11 2+9 is 11...

so the average is 55/10 or 5.5

answer at https://web2.0calc.com/questions/counting_17460

there is 6 ways it could happen: r, b, w   r, w, b  b, r,w  and so on blah blah blah

and there are 6*6*6 total possibilities so 

6/6*6*6 is 1/36

-12 to 18 is 18-(-12) which is equal to 18+12 which is 30. Double negative become positive

if you mean simplify then

first distribute the 3 in 3(2x-8) which is equal to 6x-24.

then you substract 11x from 6x-24 to get -5x-24

I think the answer is 12/19

To get no solutions the variable side must cancel out.

Since the last equation only has variables x and z, we have to cancel the y so

Multiply x+y+3z=10 by 8 to get 8x+8y+24z=80

substract the second equation to get 12x+19z=63

then we have to cancel the z

multiply the last equation by 19 to get 19xz+19z=57

 (12x+19z=63)-(19xk+19z=57) to get 12x-19xk=6

the left side of the equation must equal zero, so 12x=19xk

19k=12

divide by 19

k=12/19

-12-(-3) is -12+3 or -8. But the difference is positive so 8.

could you restate question. i think some of it got cut out

diagram???