EthanPendence

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{a}}}}}{{solve}}{\left(\begin{array}{l}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{a}}{\mathtt{\,-\,}}\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}}\right)=-{\mathtt{24}}\\ {\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{6}}=-{\mathtt{24}}\\ {\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{6}}=-{\mathtt{24}}\\ {\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{a}}=-{\mathtt{18}}\\ {\mathtt{a}}=-{\mathtt{6}}\end{array}\right)}$$

$${\frac{{\mathtt{1}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\frac{{\mathtt{2}}}{{\mathtt{3}}}}$$

You need to write the question a little differently.

$${{i}}^{{\mathtt{2}}}$$  is equal to -1

$${\sqrt{{\frac{{\mathtt{1}}}{{\mathtt{29}}}}}} = {\mathtt{0.185\: \!695\: \!338\: \!177\: \!051\: \!9}}$$

$${\frac{{\mathtt{20}}}{{\mathtt{9}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{3}}}{{\mathtt{5}}}} = {\frac{{\mathtt{73}}}{{\mathtt{45}}}} = {\mathtt{1.622\: \!222\: \!222\: \!222\: \!222\: \!2}}$$

A quotient is the answer to any division problem.

$${\mathtt{\,-\,}}{\frac{{\mathtt{3}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{3}}}} = {\frac{{\mathtt{1}}}{{\mathtt{15}}}} = {\mathtt{0.066\: \!666\: \!666\: \!666\: \!666\: \!7}}$$

$${\frac{\left(\left({\frac{{\mathtt{13}}}{{\mathtt{22}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)\right)}{{\sqrt{{\mathtt{20}}}}}} = {\mathtt{0.066\: \!065\: \!644\: \!789\: \!766\: \!5}}$$

$${\mathtt{2}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{3}}}}$$

Prime factorization of 12 leaves  $${\sqrt{{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{3}}}}$$  take out the 2s and there is your answer.