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ewewfeffebntn
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ewewfeffebntn
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Pls help cphill
The vertices of triangle $ABC$ lie on the sides of equilateral triangle $DEF$, as shown. If $CD = 5$, $CE = BD = 2$, and $\angle ACB = 90^\circ$, then find $AE$.
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ewewfeffebntn
Nov 13, 2023