+2 f(x)=x3 and g(x)=8
Given that,
x=0
In order to find second interval, we have to find the point of intersection of y=x3 and y=8
Hence, 8=x3 ∴x=2
hence the interval is, [0,2]
Area = ∫ab[f(x)−g(x)]dx where, f(x)>g(x)
In the given example, g(x)>f(x)
∴ Area = ∫02[8−x3]dx
∴A=[8x−4x4]02
∴A=[16−4]−[0−0]
∴A=12 sq.units