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Solve system of equations to get $(\frac{1}{3}, 2\sqrt{3})$, so $b = 2\sqrt{3}$

The denominator would be $5\cdot5=25$. The only ways that the product is less than 4 is when they choose (1, 1) (1, 2), (1, 3), (2, 1), and (3, 1), which is 5 cases. So, $25 - 5 = 20$, so the answer is $\frac{20}{25} = \frac{4}{5}$.