This is a right triangle, Pythagorean Theorem, problem.
If you start at Point A and walk 34 meters south to point C and from this point walk 41 meters east to Point B, you have walked the two legs, AC and CB, of right triangle ACB (with the angle at corner C the right angle). To find the straight line distance from A to B, use the Pythagorean Theorem: AC2 + CB2 = AB2 ---> 412 + 342 = AB2
---> 2837 = AB2 ---> AB = 53.3
Walking from A to C to B = 41 + 34 = 75 meters.
Walking from A to B will save you 75 - 53.3 = 21.7 meters.