Gray46

Let's do that:

2x^2 - 7x + 2 = x^2 - 6x + 3

Rearranging the equation, we get:

2x^2 - x^2 - 7x + 6x + 2 - 3 = 0

x^2 - x - 1 = 0

Now we have a quadratic equation in the form ax^2 + bx + c = 0, where a = 1, b = -1, and c = -1.

To find the roots of this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Applying the values, we get:

x = (1 ± √((-1)^2 - 4(1)(-1))) / (2(1))

x = (1 ± √(1 + 4)) / 2

x = (1 ± √5) / 2

Therefore, the roots of the equation are:

a = (1 + √5) / 2 b = (1 - √5) / 2

To find the number of integer values of x for which the inequality $5x^{2}+19x+16 > 20$ is not satisfied, we can start by simplifying the inequality:

$5x^{2}+19x+16 > 20$

$5x^{2}+19x-4 > 0$

Now, we can solve this inequality by finding the values of x that make the quadratic expression positive.

To solve the inequality, we can factorize the quadratic expression:

$5x^{2}+19x-4 = (5x-1)(x+4)$

We need to find the values of x for which the product $(5x-1)(x+4)$ is greater than zero.

For this inequality to be satisfied, either both factors must be positive or both factors must be negative.

RT = (2/5)SQ TS = (3/5)SQ

t2 - t1 = 0.75

(d / 50) - (d / 40) = 0.75

To solve this equation, let's find a common denominator for the fractions:

(40 * d) / (40 * 50) - (50 * d) / (50 * 40) = 0.75

(40d - 50d) / 2000 = 0.75

(-10d) / 2000 = 0.75

Multiplying both sides by 2000:

-10d = 0.75 * 2000

-10d = 1500

Dividing both sides by -10:

d = 1500 / -10

d = -150