z^3-ci = -88 so that means that the imaginary part of z^3 is c and than the real part of z^3 is -88. So, x^3-3xy^2 = -88 so x=2,y=4 which means z=2+4i
4a=72 so x=18
a/|a| is either -1 or 1. So, it coul be -3, -1, 1, 3.
<-4,6>, just multiply both things by 2.
So they are 90-2x,90-x, and 90. So, 180-3x=90 which means x=30 and the other two angles are 30 deg and 60 deg.
If you're gonna use a calculator then why not just do https://www.wolframalpha.com/input/?i=minimize++%7C+x+-+1+%7C+%2B+%7C+x+-+1.5+%7C+%2B+%7C+x+-+2+%7C+%2B+%7C+x+-+2.5+%7C+%2B+%7C+x+-+3+%7C
We have that 6=g(3) so h(3) = 1/(g(3)) so h(3) = 1/6 which means (3,1/6) is on h(x) so the sum of coordinates is 19/6
Subtract 14 from both sides to get x=11.
What's the question?
a) 10 * 9 * 8= 720
b) 10 * 10 * 10 = 1000
Wouldn't this be 15 c 2 = 105? Does the savory or sweet part even matter?