ImDecentAtMath

The way I would do it is first take the outcomes when all digits are different. This would be 6*5*4 or 120 outcomes. Now we can do the rest of the outcomes. First, we can see the outcome 555. Then, we can do the outcomes when the number is 55_ with the _ being an unknown digit. This leads to 5 more outcomes. There are 5 more outcomes for 5_5 and 5 more for _55. Up till now we have gotten 136 outcomes. Now we can do the ones where there are 2 6's. So we have 66_, 6_6, and _66. We can see this is just like with 2 5's, so we get 15 more outcomes. Now, there are now more outcomes, and the answer is 151 different positive 3-digit integers. 

I might've gotten this wrong, but I think I am correct.

My take on this is that if the one player that is fine either way is a spiker, there are 6*4 =24 possible teams from that. We have to add 5 more teams if the player is a setter instead of 5*5=25, since we would be overcounting the times when the player is not included.

So there are 24+5=29 teams that can be assembled.

If you are talking about a repeating decimal, your answer is 3 and 10/11. If you are rounding please explain what degree you want it rounded to. e.g. tenth, hundredth, thousandth.

Your answer is 6. We can add 4 to both sides of this inequality and get x<7. This means the highest integer that satisfies the conditions is 6. So, there are 6 positive integers that satisfy x-4<3.

We can see that Amanda took 1 and 1/2 hrs to drive 27 kilometers so her speed in kph is 27/(3/2) = 27*2/3=18 kph. Since Hunter's speed is 3 kph less, Hunter's speed is 15 kph. 

So Amanda's speed is 18 kph and Hunter's speed is 15 kph.

I think you were meaning to talk about a repeating decimal which is 9.45 with the 45 repeating. If this is the case, then your number as a fraction is 9 and 5/11

If you want to get attention, I would reccomend being a member since Melody themselves said it increases your chance of your questions being noticed.

I got a=60 and b=3/10 and so a+5b=60+5*(3/10).

When you simplify that, a+5b=103/2.