jupiterjuno12

Hello, this has been posted before. 

The rendering looks like AoPS style Asymptote... 

I am not completely sure of this answer. 
 

Both the kids and the jobs are distinct.

Therefore, we have $5 \cdot 4 \cdot 3 \cdot 2$ ways of ordering the jobs since each kid must have at least one job.

There are $5$ jobs available for the first kid, $4$ for the next, and so on.

Now we have assigned each kid a job and we have one job left.

Thus, we have $4$ choices.

$5 \cdot 4 \cdot 3 \cdot 2 \cdot 4 = \boxed{480}$. 

Please do not cheat on your AoPS homework. This is also copyright infringement as AoPS copyrights their problems. If you need help with a problem, please ask it on your classroom message board. That is a much better place as it is not considered cheating. Judging by the fact you have chosen to title it "urgent," I suggest you refrain on procrastinating to avoid a situation in which you decide to last-minute cheat. AoPS is a very good resource - learn from it! 

Here is my new account. I have accidentally posted twice as a guest.