lolzforlife

Sorry for sounding impatient.  I figured out number 2 so it no longer has to be answered!  Thanks @Rom and @Melody.

Yes, but in \(\LaTeX\), you can use \(\times\)or \times.

People do mostly avoid using an x though.

Some people use a dot \(\cdot\) (\cdot in latex) but if you write that out, you might mistake it for a decimal point.  So another alternate solution could be parentheses.

Example(s):

\(2(2)\text{ instead of }2\cdot 2 \text{ or } 2\times 2\)

Okay why am I writing a whole explanation lol.

Can you answer number 2 please?

Thank you so much!!! Both the answers were correct.

Coin \(A\)can either have more heads or less heads than Coin \(B\), but not both.

The total number of possibilities for the coin flips is \(8\cdot 4=32\).

Subtracting the number of flips that have less heads for coin \(A\)or an equal amount of heads makes \(\frac{16}{32}=\boxed{\frac{1}{2}}\).

the answer is 12

If each person shakes hands with exactly one other person, then there will be 23/2 handshakes, since two people are required to complete a handshake. This is equal to 11.5 handshakes, which is clearly impossible. We can achieve 12 handshakes by forming two rows of 11 and 12 people. Each person in the first row shakes hands a different person in the second row. This will give eleven handshakes. The leftover person must shake hands with someone, giving 12 handshakes total.