MrBigbig

0 Questions
27 Answers

+54

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(-4/5, y) = (cos theta, sin theta)
------> h = 5, a = 4, o = 3
Because it's in QII ----> sin > 0
So sin theta = + 3/5 = y

MrBigbigDec 7, 2013

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MrBigbigDec 7, 2013

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What's the height?

MrBigbigNov 8, 2013

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x = [-b +- sqrt ( b^2 - 4ac )]/(2a)

MrBigbigNov 8, 2013

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17900 = ab^13 -----(1)
500 = ab^3 ---------(2)

(1)/(2)

179/5 = b^10
b = (35.8)^0.1

a*35.8^(0.1*3) = 500
a = 500/35.8^0.3

So a = approximately 170.925
b = approximately 1.430

MrBigbigNov 8, 2013

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y-intercept -> x = 0
(1/3)(-4)^2 + 1
= 16/3 + 1 = 19/3

(0, 19/3)

MrBigbigNov 7, 2013

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5m - p = 7------(1)
7m - p = 11-----(2)

(2)-(1)
2m = 4
m = 2

->5(2) - p = 7
p = 3

So m = 2, p = 3.

MrBigbigNov 7, 2013

+54

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9x + 10 = 11x
2x = 10
x = 5

MrBigbigNov 7, 2013

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x = [12 + ( 144 + 28 )^ 0.5 ]/14
or. [12 - ( 144 + 28 )^ 0.5 ]/14

x = (6 + sqrt(43))/7 or (6-sqrt(43))/7

MrBigbigNov 7, 2013

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ln (5x-6) = ln18 - ln (x-3)
ln (5x-6) = ln (18/(x-3))
5x-6 = 18/(x-3)
(5x-6)(x-3) = 18
5x^2 -21x +18 = 18
x(5x-21) = 0
x = 0 or 21/5

BUT (5x-6) and (x-3) cannot be negative
So x>6/5 and x>3, x>3
So x can only be 21/5.

MrBigbigNov 7, 2013

+54

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0
W = F·S = FScos theta, in this case, theta = 90°
because cos90° = 0, so net work is 0.

MrBigbigNov 7, 2013

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MrBigbigNov 6, 2013

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24hr = 86400s
(86400/6)*5 = 72000 times

MrBigbigNov 6, 2013

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-3x+2y=-6 ---(1)
5x-2y=18-----(2)

(1)+(2)
2x=12 ->x=6
-3(6)+2y=-6
2y=12 -> y=6

So x=y=6

MrBigbigNov 6, 2013

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MrBigbigNov 6, 2013

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sin45° = 1/sqrt(2) = 6.81/h
h/6.81 = sqrt(2)
h = 6.81*sqrt(2) = approximately 8.740

MrBigbigNov 6, 2013

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1+(tan theta)^2 = (sec theta)^2
tan theta = 4^2 - 1= 15
tan theta = 15^0.5 or -(15^0.5)
Because it's in the fourth quadrant, so tan theta must be negative
So tan theta = -(15^0.5)

MrBigbigNov 6, 2013