There is a \(\frac{2}{10}\) chance (probability of landing on a red sector) that the player wins 3 tokens, and \(\frac{2}{10} \cdot 3 = \frac{6}{10} = \frac35\).
There is a \(\frac{2}{10}\) chance (probability of landing on a green sector) that the player wins 5 tokens, and \(\frac{2}{10} \cdot 5 = \frac{10}{10} = 1\).
There is a is a \(\frac{6}{10}\) chance (probability of landing on a blue or yellow sector) that the player loses 2 tokens, and \(\frac{6}{10} \cdot (-2) = -\frac{12}{10} = -\frac{6}{5}\).
Adding these numbers up, we get \(\frac{3}{5} + 1 - \frac{6}{5} = \frac{2}{5}\), so the answer is \(\boxed{\text{C}}\).
