Princess Sophie E

7 Questions
22 Answers

0

1263

2

+72

Physics

The time base of a cathode ray oscilloscope (CRO) is set 1ms/cm. When an alternating current signal of 200Hz is applied to the y-plate of the CR0, what is the minimum number of cycles seen on the 30cm wide screen?

Princess Sophie E Mar 25, 2014

0

1540

3

+72

The electrostatic force between two charges Q1 and Q2 at a distance r apart is given by F=(Q1Q2)/(4PieEo*r^2). What is the unit of E?

The electrostatic force between two charges Q1 and Q2 at a distance r apart is given by F=(Q1*Q2)/(4Pie*Eo*r^2). What is the unit of E?

Princess Sophie E Mar 25, 2014

0

1093

1

+72

Complex numbers

In an argand diagram, P represents the complex number such that {Z:3|Z+3|=|Z+4i|}
show that P lies on the circle and find
a)the radius of the circle
b)the complex numbers represented by the centre.

Princess Sophie E Feb 21, 2014

0

1166

2

+72

Projectiles

A projectile is fired with initial velocity 5umeters/second at an angle of projection tan inverse of (4/3).
The projectile is halfway below its maximum height at times t1 and t2.
Show that:
a) t1 + t2 = (8u/g)
b) t1* t2 = (8u^2/g^2) <read more ..

Princess Sophie E Feb 12, 2014

0

1140

2

+72

Forces

A ladder rests with its foot on smooth horizontal ground and its upper end against a smooth vertical wall.
The ladder is uniformed and weighs 300N and inclined to the wall at an angle x. What horizontal force must be applied to the foot of the ladder read more ..

Princess Sophie E Feb 5, 2014

0

1013

1

+72

Forces

A ladder rests with its foot on smooth horizontal ground and its upper end against a smooth vertical wall.
The ladder is uniformed and weighs 300N and inclined to the wall at an angle x. What horizontal force must be applied to the foot of the ladder read more ..

Princess Sophie E Feb 5, 2014

0

2044

4

+72

Math

A uniform ladder of weight w rests on rough horizontal ground against a smooth vertical wall. The vertical plane containing the ladder is inclined at an angle x to the vertical. Prove that if the ladder is on the point of slipping and U is the coefficient read more ..

Princess Sophie E Jan 24, 2014

+72

0

Fechtmeyer wrote: how would you find x in tan 31=14/x i can solve it when x is on the top but not the bottom:
well tan31=14/x
multiply both sides by x to make x the subject.
=>tan31*x=14/x*x
=>tan31x=14
i'm sure you can get x from that but if you can't just let me know.

Princess Sophie EFeb 20, 2014

+72

0

Guest wrote: whats negative 3 over 6 minus 5 over 7 simplified.
=>(-3/6)-(5/7)
look for the lcm of 6 and 7 which is 42 =>[(-3/6)-(5/7)]/42
=>(-21-30)/42
=>-51/42
=>-17/14

Princess Sophie EFeb 20, 2014

+72

0

piestanderd wrote: if 3v+2 = 7v-6 what is v?
Ok, 3v+2=7v-6
puting like terms on oneside gives
=> 2+6=7v-3v
=> 8=4v
making v the subject we divide both sides by 4
=> (8/4)=(4v/4)
=> 2=v
v=2

Princess Sophie EFeb 18, 2014

+72

0

Thanks alot Rom!

Princess Sophie EFeb 13, 2014

+72

0

Yeah u r right and i'm sorry about that. I had connection problem so i did not notice it posted twice. I'm sorry about that.

Princess Sophie EFeb 6, 2014

+72

0

Cody said b/-3 +12= 23 Solve for b.
b/-3+12=23
multiply althrough by -3 gives:
b - 36 = -69
make b the subject
=> b = -69 + 36
=> b = -33.

Princess Sophie EFeb 5, 2014

+72

0

OMG Harley!! i'm so so sorry, i did not notice the + and - sign.
Ok so (4+1/8) - (4-1/3) all that divided by 24 gives (96+3-96-8)/24 = -5/24.
Once again i'm so so sorry. The correct answer is truly -5/24.

Princess Sophie EJan 26, 2014

+72

0

4 1\8 - 4 1\3
look for the lowest common multiple of 8 and 3 or u can just multiply 8 by 3 which is 24.
41/8 - 41/3 all that divided by 24.
24/8=3, 3*41=123.
24/3=8, 8*41=328.
=> (123 - 328)/24 = -205/24

Princess Sophie EJan 26, 2014

+72

0

A)Let U be the coefficient of friction.
At limiting equilibrium, F=UR
=> U=F/R
Resolving the directions of UR an R gives:
UR-Wsin20=0
R-Wcos20=0
=> U=Wsin20/Wcos20 =tan20 =0.364

Princess Sophie EJan 23, 2014

+72

0

Thanks alot Melody, those webpages are really helpful!! Thanks:-)!!

Princess Sophie EJan 22, 2014