randomhumanbeing

There are in total

$\frac{8!}{2!2!}$ total arrangements of letters

considering arrangements of letter where the two 'L's are right next to each other, we have

$\frac{7!}{2!}$ total arrangements

and we have the same amounts of arrangements for the two 'S's being rigth next to each other

So therefore, we have

$\frac{8!}{2!2!} - 2 * \frac{7!}{2!} + 6!$ because we overcount a bit

so the answer is $\fbox{4760}$