scrutinizer

1 Questions
125 Answers

0

1038

1

+259

How to convert Mbps in MBps

Hi, I wanted to use the sci calc, but don't know how the command line should look like for converting data speed of 9.98 Mbps in MBps. Could you give me an advise?

Thanks

scrutinizer Nov 30, 2014

+259

0

Do you mean "acceptance region" (of argument)? If you do, then it's from -infinity to +infinity (the acceptance region of linear function)

scrutinizerAug 30, 2013

+259

0

-5(1-5x)+5(-8x-2)=-4x-8x => 5(-8x - 2 -(1 - 5x))=-12x => 5(-8x - 2 -1 + 5x)=-12x => 5(-3x - 3))=-12x => 5*(-3)(x +1)=-12x, dividing both sides by -3, we get 5(x + 1) = 4x => 5x - 4x = -5 => x = -5 [input]solve(-5(1-5x)+5(-8x-2)=-4x-8x,x)[/input]

scrutinizerAug 30, 2013

+259

0

Once again, if you need to solve something there must be equality sign!

scrutinizerAug 30, 2013

+259

0

-1|3x-2|=7. |3x-2| is the absolute value. Breaking free of the parentheses it looks either as (3x - 2) if 3x - 2 > 0 and the equation is -1(3x-2)=7 or (2 - 3x) = -(3x - 2) if 3x - 2 < 0,and the equation would look as -1(2-3x)=7. Hence you have two equations in one that is due to the fact that the absolute value can hide both negative and positive values of the same number or expression.

scrutinizerAug 29, 2013

+259

0

Did you mean "to express t in the terms of other variables" ?
If yes, then m + 1 = e^lambda*t => lambda*t = ln(m + 1) => t = ln(m + 1)/lambda Does t is part of the power?

[input]m= e^lambda*t -1[/input]

scrutinizerAug 29, 2013

+259

0

Hmm, then I myself have to think properly.

scrutinizerAug 29, 2013

+259

0

4x^2 - 2x where X = 2 is identical to 4*(2^2) - 2*2 = 4*4 - 4 = 12

scrutinizerAug 29, 2013

+259

0

Just incert the guven numbers into the equation. Or what sort of the expression this one belongs to - equation, one, needed to be simplified or smth else? If this is an equation it has to be equaled to something (number or expression)

scrutinizerAug 29, 2013

+259

0

depends on the sign between numbers 30 and 4x and on the value of x

scrutinizerAug 28, 2013

+259

0

e is the base of natural logarithms,a transcendental number. http://en.wikipedia.org/wiki/E_%28mathematical_constant%29

scrutinizerAug 28, 2013