scrutinizer

1 Questions
125 Answers

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1038

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+259

How to convert Mbps in MBps

Hi, I wanted to use the sci calc, but don't know how the command line should look like for converting data speed of 9.98 Mbps in MBps. Could you give me an advise?

Thanks

scrutinizer Nov 30, 2014

+259

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Maybe you would be so kind to specify the parameters you entered, for ex., what is E? Is it the square of the triangle or what? If it is, then how can the sguare be of the same value as its side? Further, you forgot to indicate the type of triangle - is it right-, acute- or obtuse- angle? Impossible to understand and therefore to solve.

scrutinizerOct 16, 2013

+259

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Solve this equation and use then the formula (x - x1)(x - x2)(x - x3) = 0

scrutinizerOct 6, 2013

+259

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1. 7sin^2theta + 3cos^2 theta = 4 => 7sin^2theta + 3cos^2 theta = 4(sin^2 theta + cos^2 theta) => 3sin^2 theta - cos^2 theta = 0.Arrived at homogeneous trigonometric equation, and since sin^2 theta is not equal to cos^2 theta and both are not equal to 0, we can divide the components by cos^2 theta:

3tg^2 theta = 1 =>tg theta = +-1/sqrt(3). Theta = +-arctg(1/sqrt(3)) + pi n = +- 30 degrees (or +-pi/6) + pi n

2. cosine is a symmetric function, therefore cos(-pi/6) = cos pi/6, hence sec theta + cos theta = 1/cos(pi/6) + cos (pi/6) = 2/sqrt(3) + sqrt(3)/2 = (4 + 3)/2sqrt(3) = 7/sqrt(3)

Your presentation of the task contains either methodic or typewriting error since 2 + 2/3 = 8/3 can be written as a single number, but in the context of this task this looks illogically.

scrutinizerOct 5, 2013

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3/5 : 1/4 = 3/5 * 4 = 12/5 = 2.4 times

scrutinizerSep 27, 2013

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Incomplete task: there must be more data, at least other side or angle. Impossible to solve.

scrutinizerSep 27, 2013

+259

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5x - 20y = 70
6x + 5y = -32 Here we can solve this systme by at least 4 methods: by summing/subtracting these equations, graphically, by substitution, and by using Cramer's Rule.

The method by substituion is when you express one variable in the terms of other from one equation and then insert it into the other . Let's do it with the second equation and express x for example:

6x + 5y = -32 => x = (-32 - 5y)/6 and insert this expression into the first one: -(5(32 + 5y)/6) - 20y = 70 => -160 - 25y/6 - 20y = 70 =>

-160 - 25y - 120y = 420 => -145y = 580 => y = -4. So we find the other variable. By inserting this value into the expression for x we find the other variable and thus solve the sustem: x = (-32 - 5*(-4))/6 = (-32 + 20)/6 = -12/6 = -2. So the answer is (-2 ; -4)

scrutinizerSep 20, 2013

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x(9x+3)=4x^2-11x+3 => 9x^2 + 3x = 4x^2-11x+3 => 5x^2 + 14x - 3. Do you need to complete the square? 5(x^2 + (14/5)*x - 3/5) = 5(x^2 + 2*(14/5) * 1/2 * x + (14/10)^2 - (14/10)^2 - 3/5) = 5(x^2 + 2*(14/10)*x + (7/5)^2 - (7/5)^2 - 3/5)) = 5((x + 7/5)^2 - 49/25 - 3/5) = 5((x + 1.4)^2 - 64/25) = 5(x + 1.4)^2 - 64/5 =

5(x + 1.4)^2 - 12.8

scrutinizerSep 20, 2013

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Depends on the statement of the task. However the most widely spread way is to use the Pythagoras theorem or the sine theoreme, you also shoud have the definitions of sine, cosine, tangent in your mind all the time. Or and I forgot Molhweide formulas as well as the tangents theorem. Apart these general paths there can be specifical ways to solve a triangle.

scrutinizerSep 20, 2013

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Where do you see equation here? It's just simple operation of division 12/-16 can be reduced to -(3/4)

scrutinizerSep 20, 2013

+259

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6(x-8)-4x=4(x-3)-2 => 6(x-3 - 5)-4x=4(x-3)-2 =>6(x - 3) - 30 - 4x = 4(x - 3) - 2 => 2(x - 3) - 4x = 30 - 2 => 2x - 6 - 4x = 28 => 2x = -34 => x = -17

scrutinizerSep 20, 2013