3−zz+1≥2(z+4) simplified: (2z+1)(z+5)z+1≥0
interval notation: (−∞,−5]∪(−1,−12]
f(3)=4
the second equation vertically compresses the original function by 1/5, horizontally compressed by 5, and horizontally shifted 5 to the left.
orig. point: (3,4)
new point: (−0.4,−4.2) or (−2/5,−21/5)