Hello Guest! This is a great question!

For the first digit, there are 10 choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

The second digit there are 26 choices, and I am not going to list them all!

The last digit has 10 choices again.

So, in all, there are 2600 possible codes.

For it to contain an odd digit, there are 10 choices for the first or second, and 5 odd choices for the other digit. This makes there be 50 choices with od numbers.

So, here is our answer. The proability is:

50/2600 or **1/52**.

I really hope this helped.

The Math Whiz