Trlck3d

Your off by 6

8*9 = 8+8+8+8+8+8+8+8+8 = 72

Well i got F = -10/3x + i(sqrt(2)*sqrt(x)/3x)

I think this should be off topic, also the format is kinda bad ngl

since 1/3 of c = 9 that means 3/3 c = 9+9+9 or 9*3. That equals 27 so c=27

Wait do 350 students have only students or also teachers

Is this a big ideas math hw/test question? I need to know before helping

1. Since 1 big box = 3 small boxes we can change it to 10 small boxes = 150. That means 1 small box hold 15. 15*3 = 45. 45-15 = 30 so your answer is 30

2. 1 small = 1/2 big. That means 7 small = 140. 140/7 = 20. So 1 small equals 20. Then 20*2 = 40 so the answer is 40

SMH next time at least remove Latex.

 By Hamilton's Theorem, the solutions are z = 4^{1/4}*e^(pi*i/4), 4^{1/4}*e^(pi*i/4 + pi/4), 4^{1/4}*e^(pi*i/4 + 2*pi/4), and 4^{1/4}*e^(pi*i/4 + 3*pi/4).  Since 4^{1/4} = sqrt(2) and e^(pi*i/4) = (1 + i)/sqrt(2), the first solution is 1 + i.  Then the other roots work out as

4^{1/4}*e^(pi*i/4 + pi/4) = 1 - i,

4^{1/4}*e^(pi*i/4 + 2*pi/4) = -1 - i, and

4^{1/4}*e^(pi*i/4 + 3*pi/4) = -1 + i.

BTW this is taken from another post and not made by me