tuffla2022

I got this in GeoGebra

How many teams in total?

Thanks for that on. I'm obviously out of shape when it comes to geometry. Should have seen that $\Delta ABE \cong \Delta ADF$. That is what solves this. Very good explanation of this.

24 - (8:30 - 3:15) = 24- 5:15 =18:45 =$18\; \frac{3}{4} \; hours$

D is correct.

Well, seems like we agree on the answer, but I haven't seen Your cool technique before. You learn something new every day.

a) 3m + 3x3m = 3m + 9m = 12m

You can find my tinker-project here:

Hm. Tried this one. by tinkering in GeoGebra. Not too easy. Maybe I'm getting a bit tired... By tinkering I found that AB is between 16.6, and that gives an area around 332, if all conditions are met. I am too tired right now to think out a way to calculate this.

Sorry, didn't notice that there had to be 3 digits. I stand corrected by Guest below. Code has been updated.

Exercise 1:
There are 30 integers in that group, they are:
105, 135, 165, 195, 225, 255, 285, 315, 345, 375, 405, 435,
465, 495, 525, 555, 585, 615, 645, 675, 705, 735, 765,
795, 825, 855, 885, 915, 945, 975

$\frac{r-3}{\sqrt{r}} = -2\times\sqrt{r}\\ r-3 = -2\times \sqrt{r} \times \sqrt{r} = -2 \times r\\ r-3 = -2 \times r\\ 3 \times r = 3\\ r = 1$

On ex. 1 python says:

There are 33 integers in that group, they are:
15, 45, 75, 105, 135, 165, 195, 225, 255, 285, 315, 345,
375, 405, 435, 465, 495, 525, 555, 585, 615, 645, 675,
705, 735, 765, 795, 825, 855, 885, 915, 945, 975

Maybe I misunderstood. Is this an ongoing thing? Ie: I post one operation, the next posts the next one and so on?

Okay, I'll go with: 1 + 5 = 6

Linda: L, Miah: M, Noah: N

L+M = 11. L+N = 19, M+N = 22 or whatever order You place them in.

L = 11 - M, 11 - M + N = 19, so M = N - 8, and so N - 8 + N = 22, or 2N = 30, so N = 15

Going back, we find that M = 15- 10 = 5, and L = 11 - 5 = 6. So the largest number is 15.

As before, use the onilne calculator, here is the answer:

You can use an online calculator for that, the solution, and the calculator can be found at:

Here is my doodle

It seems like swapping the even numbers around with eachother would do the trick. In this series there are 4 even numbers, they can be rearranged in 4! ways or 4x3x2x1 = 24.

My go at this one: