Williamcarroll

Hello,

 

The line L, represented by the equation y = 5x + 6, intersects the graph of y = x^2 at two distinct points P and Q. Analyzing the equations, we can find the intersection points by equating the expressions for y:

 

Substituting y from the equation of line L into the equation of the parabola, we get: 5x + 6 = x^2.

Rearranging the equation gives the quadratic equation: x^2 - 5x - 6 = 0.

Solving the quadratic equation yields two values for x: a and c.  TKMaxxCare

Substituting these x-values back into the equation of line L, we find the corresponding y-values: b and d.

 

The resulting points P(a, b) and Q(c, d) are the intersection points of the line and the parabola. The line intersects the parabola at these points due to their shared coordinates (x, y). The solution ensures that a < c, as the line starts below the parabola and then crosses it. Thus, the line L intersects the graph of y = x^2 at the distinct points P and Q, satisfying the given conditions.

 

I hope the information may helps you. 

Hello,

 

The probability that Hamza rolls the same two numbers as George, though not necessarily in the same order, can be calculated using the concept of combinations.

There are 6 sides on a standard fair-sided die, so the total number of possible outcomes for George's roll is 6 * 6 = 36.

Now, let's consider the number of favorable outcomes where Hamza rolls the same two numbers as George, not necessarily in the same order. In this case, Hamza's roll can be thought of as choosing 2 numbers out of the 6 possibilities, without regard to order.  TKMaxxCare

This can be calculated using combinations: C(n, r) = n! / (r! * (n - r)!), where n is the total number of possibilities (6 in this case) and r is the number of choices (2 in this case).

C(6, 2) = 6! / (2! * (6 - 2)!) = 15

So, there are 15 favorable outcomes where Hamza rolls the same two numbers as George, not necessarily in the same order.

The probability is then the ratio of favorable outcomes to total outcomes:

Probability = Favorable Outcomes / Total Outcomes
Probability = 15 / 36
Probability = 5/12

Therefore, the probability that Hamza rolls the same two numbers as George, though not necessarily in the same order, is 5/12 or approximately 0.4167.