I suggest you read this similar question
Try figuring it out by yourself.
A=2/3=50/75
B=1536
C=8/25=24/75
D=-16
E=\(3\sqrt{2}\)\(\approx4.24264068\)
So the order is
\(C,A,E,D,B\)
Compute \(\dbinom53+\dbinom63+\dbinom73\).
USE THE HOCKEY STICK THEOREM (See this).
See that \(\dbinom53+\dbinom63+\dbinom73=\dbinom84-\Bigg[\dbinom43+\dbinom33\Bigg]=\dbinom84-\Bigg[\dbinom41+\dbinom30\Bigg]=70-(4+1)=\boxed{65}\)
Otherwise there would either be zero solutions or infinite.
Sorry, I am unable to solve your problem. For two variable equations to be solved, there must be two equations.
