GingerAle

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UsernameGingerAle
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Questions 4
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 #8
avatar+2440 
+1

Yep seems like a normal lottery to me, Except that the super balls would normally be numbered from 1 to 10 instead of 21 to 30.

 

 

In lotteries with super balls, the super balls are a separate set and a different color, and the ball is drawn separately from the other balls – in other words, these are independent events.  If they were not independent then a super ball may not be drawn at all or three super balls may be drawn and none of the others.

 

To find the over all probability

 

First, calculate the probability of matching 2 of three numbers drawn from a pool of 20 numbered balls.

 

1)       Number of ways to select 3 balls from 20 

                20! / (17! * 3!)  =  nCr(20,3) = 1140

 

2)       Number of ways select to 2 balls from 3 balls

                (3!) / ((2!)*(3-2)!) = 3

 

3)       Number of ways to select 2 matching balls and one none matching ball in a draw of 3                      from 20 balls

                (20-3)! / (((20-3) - (3-2))! * (3-2)!) = 17

 

4)       Number of ways of matching 2 balls in a draw of 3 from 20 balls

                 3*17= 51

 

5)       Probability of matching 2 balls in a draw of 3 from 20 balls

           51/1140 = 0.04473684 or 1 in 22.353

                 

Second, calculate the probability of matching 1 of 10 numbers drawn

This is easy it is just 1 in 10.

 

Winning requires a match on the first OR second draw. (You could match both, but that is irrelevant here.)

 

The probability of winning is the same as the rate of winning.  On average, a win will occur 1 in every 22.353 draws for the first set, or 1 in every 10 draws for the second set.

 

To find the over all probability of having a win, average the two rates.

 

The word “rate” offers a clue for the proper type of average to use. When averaging rates, use the harmonic average.

 

H = 2/ (1/10 + 1/22.353) = 13.8182

 

This equates to each of the draw events having a (1/13.813) probability of matching; but remember there are 2 events, so multiply this by 2.  (1/13.813) * 2 =  0.1447

 

Over all probability 14.47%

Jul 2, 2017
 #2
avatar+2440 
+1

Well, Mr. Blarney Bag, like usual, you are wrong. This calculator can display a fully resolved mantissa of at least 2048 digits. You just have to know how to use it. I could explain it but you need to be smarter than the machine to understand it. So, that leaves you out.

 

This equation is a solution to the probability of two persons NOT sharing the same birthday (date) in a group of thirty persons.

 

Alan elaborates on the equation (not the probability), here.

And he presents a much more clear method of entering it into the calculator, here.

 

****

Correction on  comment

This equation is a solution to the probability of two persons NOT sharing the same birthday (date) in a group of thirty persons.

The original read:

This equation is a solution to the probability of two persons sharing the same birthday (date) in a group of thirty persons.

 

1-(npr(365,(365-335))/365^30)   is the  solution to the probability of two persons sharing the same birthday (date) in a group of thirty persons.

Jun 27, 2017
 #8
avatar+2440 
+2

Actually, they are not interpreted same. Each interpretation gives a different solution for x.

 

As Hectictar pointed out:

Sir Alan’s interpretation is: 4^(2^x) + 2^(2^x)  =  56

And Sir  CPhill interpretation is:     (4^2)^x + (2^2)^x  =  56 

 

Sir Alan’s is interpretation is exactly the same as the asked question. (This follows power-tower convention, where stacked powers are multiplied from right to left or from the top down, and the resultant product becomes the exponent to the base number.)

 

 Sir CPhill’s solution starts with the base then increments the value by each ascending power.

 

The solutions for these interpretations give different results for the value of x.

-----

 

\(\text{For Sir Alan's solution}\\ x = log_2 (log_2(7))\\ x \approx 1.4892114692\\ \text{ }\\ \text{For Sir CPhill’s solution}\\ 2x = \dfrac {log (7) } { log (2)}\\ x= \dfrac {log (7)/ log (2)}{(2)}\\ x\approx 1.4036774610\\ \)
-----

 

Sir Alan notes the calculator input error of the questioner; however, the questioner may have correctly entered this into the site calculator

 

(4^2^log(log(7, 2), 2)) + (2^2^log(log(7 , 2), 2) )  

The calculator would interpret it as

(4^2)^(log(log(7, 2), 2)) + (2^2)^log(log(7 , 2), 2))

The site’s calculator does NOT follow hierarchal convention in interpreting stacked powers.

Here is an elaboration on this issue:

Use of parenthesis to, in this case, force proper hierarchal convention

 (4^(2^log(log(7, 2), 2)) + (2^(2^log(log(7 , 2), 2)

gives 56 as the result.

 

Which value of x is correct? Only the asker’s hairdresser knows for sure.smiley

Jun 22, 2017
 #1
avatar+2440 
+1

how many dogs can fit in heaven?

 

In people-heaven, none. They voted a long time ago to kick all dogs out of people-heaven, because they were tired of stepping in dog dirt. After they were kicked out, the dogs went to dog-heaven.    In dog-heaven, bunches can fit.  This is where I want to go. Dogs don’t mind people coming there –they even let cats in. I have my own pooper-scooper.   

 

who started time?

I did. As soon as I start answering these questions, I started time. Wasting time, but I started it.  

 

when do people start to remember?

I used to know the answer to that but I can’t remember.

 

are we too evolved?

After reading and answering these questions, I am certain we are not.  

 

will we ever find something in space worth leaving our home for?

Yes. Just ask Neil Armstrong.

 

is there anything out there?

Yes. There are lots of rocks. Lots and lots of them.  There’s also some space junk.

 

are we insignificant?

For sure, I am not. You, however, are decidedly insignificant. 

 

why is space so big?

For the same reason that your brain is so small.

 

is there a higher power?

Yes, there is always a higher power. Take X to the power of Y, for any value of Y you choose, I can choose a higher one.  

 

what is at the core of the earth?

Evil people and a few really bad dogs. That is where heII is. Evil people are mostly composed of ion and nickel, though.   I’m not sure what the bad dogs are composed of --dehydrated vomit or cat-food, maybe.

 

if someone got down there, do you think the could control the earths movement through space?

A long time ago, they could control the Earth’s movement through space, but the panel was deactivated and control transferred to heaven. I’m not sure if it was people-heaven or dog-heaven. We should know in a few more years, though. If the Earth goes to the dogs then it was dog- heaven, if it’s just generally screwed up, then it was people-heaven. If Earth goes to heII then obviously they regained control.   

 

If you have any more questions, just ask. I usually make some time to waste.  

Jun 22, 2017