Alan

$${\mathtt{G}} = {\frac{{\mathtt{64.32}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left({\mathtt{14}}\right)}{\mathtt{\,\times\,}}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left({\mathtt{11}}\right)}\right)}^{{\mathtt{2}}}}{\left({\mathtt{6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left({\mathtt{24}}\right)}{\mathtt{\,\times\,}}{\mathtt{6.4}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left({\mathtt{23}}\right)}\right)}} \Rightarrow {\mathtt{G}} = {\mathtt{0.000\: \!000\: \!000\: \!067}}$$

G ≈6.7*10^-11 m³/(kg.sec²)

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$$G=F\frac{d^2}{m1m2}$$

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$$F=G\frac{m1m2}{d^2}$$

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This method can be found in computers that use binary arithmetic (where they use 2's complement of course).  

I've never come across 9's complement being used for real in normal base 10 arithmetic though!

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Energy of photon = hc/λ where h is the Planck constant (h = 6.6260693*10^-34 joule.sec), c is speed of light (c =  299792458 m/sec) and λ is wavelength (λ = 670.8*10^-9 m)

So:  Energy = 6.6260693*10^(-34)*299792458/(670.8*10^-9) ≈ 3*10^-19 joules

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If this is 4s² - 4s + 1 then:

The coefficients of the polynomial are 4, -4 and 1.

Because it can be written as (2s - 1)² there are two, i.e. repeated zeros, both at s = 1/2 

If it is 4s² -4(s+1) then:

The polynomial is 4s² - 4s - 4 with coefficients 4, -4 and -4.

It doesn't factor so it's zeros are:

$${\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{s}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{s}}{\mathtt{\,-\,}}{\mathtt{4}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{s}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{5}}}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\
{\mathtt{s}} = {\frac{\left({\sqrt{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{s}} = -{\mathtt{0.618\: \!033\: \!988\: \!749\: \!894\: \!8}}\\
{\mathtt{s}} = {\mathtt{1.618\: \!033\: \!988\: \!749\: \!894\: \!8}}\\
\end{array} \right\}$$

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The 9's complement of 678 is 321

321 + 345 = 666

The 9's complement of 666 is 333 which is the desired result.

(i.e. 678 - 345 = 333)

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6^-4 = 1/6⁴

$${{\mathtt{6}}}^{-{\mathtt{4}}} = {\frac{{\mathtt{1}}}{{\mathtt{1\,296}}}} = {\mathtt{0.000\: \!771\: \!604\: \!938\: \!271\: \!6}}$$

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This will be :  1799999*(1 - 13.99/100)

$${\mathtt{1\,799\,999}}{\mathtt{\,\times\,}}\left({\mathtt{1}}{\mathtt{\,-\,}}{\frac{{\mathtt{13}}}{{\mathtt{100}}}}\right) = {\mathtt{1\,565\,999.13}}$$

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