Alan

As \(\sqrt{27}=\sqrt{3^3}\rightarrow3\sqrt{3}\)  then \(\sqrt{3}+\sqrt{27}\rightarrow\sqrt{3}+3\sqrt{3}\rightarrow4\sqrt{3}\)

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To find the log to the base 5 of n, enter log(n,5)

The parentheses are unnecessary here.  

4x - 3 + 3x + 1 = 180

7x - 2 = 180

7x = 182

x = 182/7 

x = 26

Let the width of the square cross section be w.  Then 9*w^2 = 1 so w = sqrt(1/9) = 1/3 m

The volume of a cube of width w is therefore w^3 or 1/27 m^3

This weighs 9002/27 kg.  

See reply at http://web2.0calc.com/questions/wow-i-don-t-know-how-to-take-this-limit#r4 

Have a look at this Youtube video:  https://www.youtube.com/watch?v=n0VFDT3ZObY for a proof.

One way of defining e^x is  \(e^x=lim_{n\rightarrow\infty}(1+\frac{x}{n})^n\)

Like so:

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p = 0.2,  q = 0.8

Prob of exactly 2 ethnic minorities:  p^2*q^8 → 0.2^2*0.8^8 → 0.00671