If we put this in the form a+bi

We first start by doing \(\sqrt{3}*\sqrt{-6}=\sqrt{3}*\sqrt{3}*\sqrt{-2}\) so this would result in the answer being \(3\sqrt{-2} \) or \(3\sqrt{2}i\) so

B= \(3\sqrt{2}i\)

So then solving for 6i*i then we know that \({i}^{2}\) is equal to -1 so we know that -6.

This means that it would be -6+ \(3\sqrt{2}i\)

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