complex numbers

If we put this in the form a+bi 

We first start by doing $\sqrt{3}*\sqrt{-6}=\sqrt{3}*\sqrt{3}*\sqrt{-2}$ so this would result in the answer being $3\sqrt{-2}$ or $3\sqrt{2}i$ so 

B= $3\sqrt{2}i$

So then solving for 6i*i then we know that ${i}^{2}$ is equal to -1 so we know that -6.

This means that it would be -6+ $3\sqrt{2}i$