AzizHusain

sqrt6x^3 / sqrt3x = sqrt(2x^2)*sqrt(8x^2) = sqrt(16x^4) / A.

Using dimensional analysis:

1 m^3 X ((100cm)^3 / 1m^3) X (1 mL / 1 cm^3) X (1 L / 1000 mL) = 1,000,000 / 1,000 = 1,000 L.

Those are the variables: x = number of flags, y = number of square yards, & z = total cost -->

In verbal form:

The number of square yards needed is equal to 0.6 times the number of flags required. The total cost of the material will be 2 times the square yards needed.

Since each flag requires 0.6 square yards of material and the material costs $2 per square yard:

Let x = number of flags & y = number of square yards needed -->

y = 0.6x

Then, let z = total cost of the material -->

z = 2y

EDIT: It should be z = 2y; I had written 1.2 before.

2+sqrtx+5=4 --> 

sqrtx = -3 --> No solution since square root of x will be positive.

5(3x+1)¼=10 -->

(3x+1)¼= 2 -->

(3x + 1) = 8 -->

3x = 7 -->

x = 7/3.

25 1/2 as in 25^(1/2) --> sqrt(25) = 5.

(sqrt9xy^2)^4 --> (sqrt9xy^2)(sqrt9xy^2)(sqrt9xy^2)(sqrt9xy^2)

(sqrt9xy^2)(sqrt9xy^2) = 9x^2y^4

Now, we can just square this term [9x^2y^4] since we have another (sqrt9xy^2)(sqrt9xy^2) -->

(9x^2y^4)(9x^2y^4) = 81x^4y^8.

An easier way is to just distribute the ^4 to each of the terms -->

(sqrt9xy^2)^4 = (sqrt9)^4*x^4*(y^2)^4 = 81x^4y^8.

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EDITED: First answer.

More information is needed; however, if you are looking for the total wages for a week: $9.00/hour --> 40 hours a week = 40 hours/week*($9.00/hour) = $360/week.

4.466^x -2(2.331)^x + 1 = 0

4.466^x - 4.662^x = -1 -->

-0.196^x = -1 -->

log(-0.196^x) = log(-1) -->

Properties of logs allow: x log(-0.196) = log(-1) -->

x = log(-1) / log(-0.196) = Error

However, when plugging in values such as x = 0.02 into -0.196^x = -1, we obtain a number that is close to -1, -0.9679326095185039.

9.075 X 10^-6

(5x3 + 2x2 + x - 1) - (2x3 - 3x2 + 4x)

Distribute the negative sign: 5x3 + 2x2 + x - 1 -2x3 + 3x2 - 4x -->

Combine like terms: 2x^3 + 5x^2 -3x - 1.