Hello Guest!
Let's start by setting the sides of our rectangle as x and y.
2x + 2y = perimeter
x*y = area
Thus, our equation is x*y = 4(2x + 2y)
x*y = 4(2x + 2y)
x*y = 8x + 8y # Distribute
x*y - 8x - 8y # Subtract 8x + 8y to both sides
The next part is kinda complicated.
(x-8)(y-8) = xy - 8x - 8y + 64
So (x-8)(y-8) = -64
The smallest possible perimeter will be when x and y are very close, but since it's not a square, x and y can't be equal, x-8 and y-8 both must be positive integers too.
Out of our factors of -64, -8 and 8 are the closest to each other. However, this doesn't work because for y - 8 = -8, y is equal to 0.
The next closest factor is -4 and 16.
x - 8 = 16
x = 24
y - 8 = -4
y = 4
Thus, our side lengths are 4 and 16 making the perimeter 40. :)))
I hope this helped.
=^._.^=