May anyone help me here!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!??!?!?!??!!?!
$$\dfrac{10\sqrt{40}}{\sqrt{5}}=\boxed{42.29485053762256}$$
What is so hard???
Can you guys help on the following?
$$\dfrac{3a^3(16-a^2)}{12a^6(a^2-9a+20)}$$
I got to the part:
$$\dfrac{1(16-aa)}{4a^3(a^2-9a+20)}$$
I don't know what to do next. Can you pleas tell me what to do next?
And
- + = answer depends on which integer is greater, the positive, or the negative.
Oh no... I am tripping too much...
Oh! I get the answer now! Melody, how do you know it is my first MathWay question? This is my third, but I didn't post it here...
Just put the 1/2 after the 6, and then subtract 1/1 from 6.
$$-\dfrac{1}{2}+6=\boxed{5.5,\;\mbox{or\;}5\dfrac{1}{2}}$$
Melody, you're answer is not on the sheet.
May someone explain how you canceled out aa???
And can someone help me figure out to do in the following problem please?:
$$\dfrac{6a^2-30a+36}{4a-12}$$
How do I start off, and can you give an example of how to do it?
