#1
+12 B. There are many ways to solve this the simpliest is you have 52 card, you cant draw that card again but you can draw any other card in the deck so that is 51 possibilities for each card so it would be 52*51, and get the answer given, this is if the order of the cards given matters, if it does not it would be alot more complex i remember getting this problem when i was in pre-calc, the question is worded incorrectly dont worry about it.
C. for this one, You are looking for the possibilities of getting ace of diamonds, and an ace of spades, you could draw the ace of diamonds first then the spade or the ace of spades first then the diamond so thats two possibilities. You are looking for the probability of draw that combination of cards, out of all the possible combinations you could have drawn. You know from the previous question there are 2652, possible combinations. and then as previously stated there are only 2 ways to get an ace of diamonds and spades. so
1/1326
D. 1. To get 2 twos you could first draw one two of any suit and then draw a second two of any of the three other suit so that would be 4*3,
or you could do it out
2 of spades first
Second
1. Diamond
2. Club
3. Heart
2 Heart first
4. Spade
5. Club
6. diamond
so on
so you have 12 possibilities out of the 2652 total possible combinations. so 12/2652, or 1/221
D2. same idea 13 diffrent possibilties to choose from the first time 12 the second. (13*12)/2652 = 1/17
