ElectricPavlov

This should clear things:

6(x+8) ≥ ‒43+4x    Expand L side

6x + 48 >= -43+4x     subtract 4x from both sides

2x + 48 >= -42          subtract   48 from both sides

2x >= -90                  divide both sides by 2

x > = - 45          Done!

Three rectangles    6 x 4        10 x 4        and       8 x 4

TWO triangles   6 x8       area of triangle = 1/2 b h      sooooo 2 * 1/2 * 6 * 8      Add all of these together = ........ mi ²

l  = w+7

perimeter =    2 (w+7)  + 2w = 86

                              w = 18

kx^2 + 3kx -4 = 0     for equal roots, the disciminant of the Quadratic Formula must = 0

b^2 - 4ac

9k^2 - 4(k)(-4) = 0

9k^2 +16k = 0

k = -16 /9     or    0 (throw out)  

Please proof read you Q and include the pertinent numbers,,,,,

Speed of bus₁ = x

Speed of bus₂  = x-14  k/hr

After 6 hours        6x      +      6 (x-14) = 1356      solve for x    , the speed of bus_{1   ....} then bus₂ = x -14 k/hr

=  6^1/4  /  6^1/5   = 6^(1/4-1/5)   = 6^??       I think you should be able to finish

Find the length of ZX   by   tan 70  =      ZX /3

Use this ZX   and the arcsin function of  ZXY  to  calc   ZXY^o

x^2 + 10x + 25 = 8.

x^2 + 10x + 17 = 0     use quadratic formula to find    x=−5± 2 sqrt2       you can take it from here......