ElectricPavlov

Need more info...or a diagram.....is this in a triangle?   ...or what?

3rd + 6th term = 25        let x = third term

x + 3d = 25

AND    x - 2d= 2         x = 2 + 2d

sub into the first equation

2 + 2d + 3d = 25

5d = 23

d = 23/5

1st + 3d = 4th term

2 + 3 (23/5) = ........

IF your equation is correct    just put   0 in for height ('y')    and solve the equation for 't'   (likely via the quadratic formula  throw out any negative 't' values found)

Given   density    and volume       mass = density * volume   (make sure they are all in the same UNITS !!)

there are   6+8 = 14 apples

2  +  14   + Orange = 3 (14)

  16 + O = 42     subtract 16 from both sides to find # O

6 (x^2+2x)   -3 (y^2+6y) = 3       complete the square for x  and y

6 (x+1)²  - 3 (y+3)²   =   3 +6 -27    = -18    divide both sides by   -18

(y+3)²  / 6   -  (x+1)² / 3 = 1

DBC - DBE = EBC

(12x-3)   -   (5x+12)     =   (3x+13)      solve for 'x'   then EBC  = 3x + 13

If it is a CUBE shaped box, the side length will have to be 12 inches to match the height

12 x 12 x 12 = 1728 in³

Vertex is 3,1   from the graph

Vertex form of parabola

y = a ( x-3)^2 + 1    sub in another point to calc a = -1

y = - (x-3)² + 1

slope of given line, m = -3     perpindicular = -1/m   = 1/3

Point slope form (using the point given)

(y+6) = 1/3 (x-5)