Conver the equation 6x^2 - 3y^2 + 12x - 18y - 3 = 0 to the standard form of a hyperbola.
6 (x^2+2x) -3 (y^2+6y) = 3 complete the square for x and y
6 (x+1)2 - 3 (y+3)2 = 3 +6 -27 = -18 divide both sides by -18
(y+3)2 / 6 - (x+1)2 / 3 = 1
+36915 
