I think you have the h,k backwards in your parentheses.... first equation (-2-h)^2 + (0-k)^2 = r2
second equatio (2-h)^2 + (0- k)^2 = r^2 third equation (3-h)^2 + (2-k)^2 = r^2 Solve for h k r
152 + ?1 = 180
Then when you find '?1 The Other? = 180- ?1 -114
Just add the two given angles 130 + 80
I can tell you 1 and 4 Are the same measure
if the upper and lower slanted line as are parallel, Then 1 4 6 8 are all the same measure
249 in base 11 = 9 + 4 x11 + 2 x 11^2 3ab in base 12 = 12 + 11x12 + 3 x12^2 Add all of that together.....
(4x-5)(2x+3) - (x-8)(3x+2) = area
8x^2 +12x-10x -15 - 3x^2 -2x+24x+16 = area
5x^2 +24x +1 = area
Angles sum to 180 in a triangle
b + b-12 + 2b-8 = 180
Solve for b Then a = b-12 c= 2b-8
1/8 + 1/4 + 1/9 = 1/x Solve for x The hours required for all 3 working
New area - Original area = Difference in area
2x^2+ 6x +4 - 2x^2 = 6x +4
The two angles are supplementary....They sum to 180....a straight line
so 3x+5 + 10x-7 = 180
solve for x Then compute the values of each angle....
