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Express \(249_{11}+3AB_{12}\) as a base 10 integer. Here A and B denote the digits whose values are 10 and 11, respectively, in base 12.

 

 

 

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 Sep 7, 2020
 #1
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249 in base 11 =  9   +     4 x11     +     2 x 11^2
3ab in base 12 = 12   +    11x12    +    3 x12^2           Add all of that together.....

 Sep 7, 2020

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