Express \(249_{11}+3AB_{12}\) as a base 10 integer. Here A and B denote the digits whose values are 10 and 11, respectively, in base 12.
Thanks
+36916 249 in base 11 = 9 + 4 x11 + 2 x 11^2
3ab in base 12 = 12 + 11x12 + 3 x12^2 Add all of that together.....
