Vertex (3,2) form of a parabola
y = a(x-3)^2 + 2 sub in point 1,0 to calculate a
0 =a(1-3)^2 + 2 a =-1/2
y = -1/2 (x-3)^2 + 2 Now expand and put into form ax^2 + bx + c to get your final answer
8 = 20 (1-.5)t Where t = # of half lifes
t = 1.3219 half lifes
1.3219 x 1620 = 2141.5 yrs
Plug in the data to see which equation works
example 5 boxes = 20.40
second equation
5* (3.6) = 18 18 does not = 20.40 so second equation is NOT the answer.....try the others to find the correct one
always a good idea to try one of the other data sets when you think you have the right eqution as a check
112 = 7 * 2 * 2 *2 * 2
98 = 7 * 7 * 2
Slope, m, of given line is -3/4 perpindicular is - 1/m = 4/3
A and C have slopes of 4/3 .... plug in 12,9 to see which equation it is.....
(6*12^0 + 10*12^1 + 4 * 12^2 + 1 * 12^3 ) - ( 9*12^0 + 11*12^1 + 5* 12^2 )
Then convert the result back to base12
87 coins total
x = nickels
then 87- x = quarters
value
5 x + 25 (87-x) = 1395 solve for 'x' = number of nickels then quarters = 87-x
3x^2-18x+55 divide first part by 3
3 ( x^2-6x) + 55 'complete the square'
3 (x^2 -6x +9) -9 + 55 simplify
3 ( x-3)2 + 46 You can finish......
Draw a V enn diagaram and complete it to find 81 dogs in the school
a 2^r = 1 and a 64^r = 4
2^r = 1/a (2^6)^r = 4/a
(2^r)^6 = 4/a
(1/a)^6 = 4/a
1 = a^6 * 4/a = 4a5
a = (1/4)1/5 = .757858283
then a 64r = 4
.757858283 * 64r = 4
r = .4