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I am not sure how to do this, since it is a reverse quadratic question. Thanks!

 

Suppose that we have an equation y = ax^2+bx+c  whose graph is a parabola with vertex (3, 2) , vertical axis of symmetry, and contains the point (1, 0).

What is (a, b, c)?

 

Thanks for your help!

 Oct 6, 2020
 #1
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Vertex (3,2) form of a parabola

y = a(x-3)^2 + 2   sub in point 1,0 to calculate a

0 =a(1-3)^2 + 2        a =-1/2

 

y = -1/2 (x-3)^2 + 2       Now expand and put into form   ax^2 + bx + c    to get your final answer

 Oct 6, 2020

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