I am not sure how to do this, since it is a reverse quadratic question. Thanks!
Suppose that we have an equation y = ax^2+bx+c whose graph is a parabola with vertex (3, 2) , vertical axis of symmetry, and contains the point (1, 0).
What is (a, b, c)?
Thanks for your help!
+36916 Vertex (3,2) form of a parabola
y = a(x-3)^2 + 2 sub in point 1,0 to calculate a
0 =a(1-3)^2 + 2 a =-1/2
y = -1/2 (x-3)^2 + 2 Now expand and put into form ax^2 + bx + c to get your final answer
