A put in x=10 to show the same value is calculated on each side of the equation
B x cannot be -1/2 the denominator would be zero....not allowed
C Put Right side over common denominator (2x+1)
[ 2x^2 (2x+1) + 5 (2x+1) + 4 ] / (2x+1)
[ 4x^3 + 2x^2 + 10x + 5 + 4 ] / (2x+1) This exactly the same as the expression on the LEFT
so any 'x' value (except -1/2) will make this equation true