a) y = max height = 12
x = point of max height = 18
b) vertex form of parabola
y =a (x-18)^2 + 12
0 = a ( 324) + 12 ( at x = 0 y = 0 so calculate 'a' values here)
-12/384 = a = - 1/32
y = - 1/32 (x-18)^2 + 12
2.2 = - 1/32 (x-18)^2 + 12 What value of x produces a y value of 2.2 m ?
x = 35.70 m from kickoff point this ignores air friction and assumes the ground is level playing field
