b(b^4 * b^5)^2 = b^x
b ( b4+5 )2
b ( b9*2)
b19 = bx x = 19
6.54+6.09 = 12.63 liters
(12.63 - 1.68) / 3 =10.95/3 = 3.65 l in each container
shaded area is everything greater than the line ( does not include the line ....because it is dashed)
line equation y= x-7
shaded area is thus y>x-7
a (1^2) + 5 (1) = 3
a + 5 = 3
a = - 2
-2x^2 + 5x - 3
(-2x +3 ) ( x-1) =0
- 2x+ 3 = 0 x = 1.5 is the other solution
Dome shaped parabola max occurs at t = - b/2a = - -60/(2*-16) = - 1.875
sub this value into the equation to find the max height
-16 (- 1.875)2 - 60 ( - 1.875) + 54 = max height in feet I'll let you finish....
final misture is 9 liters
inputs
.10 (6) and .15 (3)
.10(6) + .15(3) = x ( 9)
(.6 + .45 )/9 = x = .116666 or 11 2/3 %
The product of five and two multiplied by the product of three and fifteen.
a x^2 + 18x + 9 divide by 9
a/9 x^2 + 2x + 1 a/9 = 1 so a = 9
9* (x+1)^2 =
(3x+3)2
4a + 2e = 18
3a + 5e = 31 multiply first equation by -2.5 to get
-10a -5e = -45 add bottom two equations ( this will eliminate the 'e' variable)
- 7a = -14
a = 2 dollars
30 min / 6 k = 5 minutes per keychain
9 keychains * 5 minutes per keychain = 45 minutes
