The equation y = -16t^2 - 60t + 54 describes the height (in feet) of a ball thrown downward at 60 feet per second from a height of 54 feet from the ground, where t represents time, measured in seconds. What is the maximum height of the ball? Express your answer as a decimal rounded to the nearest hundredth.
+36916 Dome shaped parabola max occurs at t = - b/2a = - -60/(2*-16) = - 1.875
sub this value into the equation to find the max height
-16 (- 1.875)2 - 60 ( - 1.875) + 54 = max height in feet I'll let you finish....
