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The equation y = -16t^2 - 60t + 54 describes the height (in feet) of a ball thrown downward at 60 feet per second from a height of 54 feet from the ground, where t represents time, measured in seconds. What is the maximum height of the ball? Express your answer as a decimal rounded to the nearest hundredth.

 Apr 11, 2021
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Dome shaped parabola      max occurs at t = - b/2a =  - -60/(2*-16)  = - 1.875

sub this value into the equation to find the max height

 

-16 (- 1.875)2 - 60 ( - 1.875) + 54   = max height in  feet          I'll let you finish....

 Apr 11, 2021

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