ElectricPavlov

I found this with a quick internet search:

Is kinetic friction equal to applied force?

If the externally applied force (F) is equal to the force of kinetic friction, Fk, then the object slides at constant velocity, and the coefficient of friction involved is called the coefficient of kinetic friction, μk.

I think that applies to STATIC friction, but kinetic friction force and force to move object w/out accel are the same as I recall.

If there is no acceleration, then the forces are balanced....the pushing force is exactly the same in magnitude as the force of the KINETIC friction.      264 N     although it is in the OPPOSITE direction as the frictional force.

4 kg is 4000 gm

4000 - 2570 = 1430 gm  = 1.43 kg = how much more the dog weighs (until the dog EATS the cat !)

Hang on just a sec ILT

1/10 * 2/10 = 2/100   =  1/50

        When you MULTIPLY fractions the numerator AND denominator get multiplied ...alike or not.

I assume S8 is a molecule of 8 Sulfur atoms    Sulfur 32.06    8*32.06 = 256.48 gm    per mole

                C60 is a molecule of 60 Carbon atoms   Carbon 12.011   12.011 * 60 = 720.66 gm  per mole

If you are given a point  x,y    then displacement from the origin is   sqrt(x^2 + y^2)

   Can you be more specific?

Show that two sides are parallel ...they have the SAME slope.

Show that the OTHER two sides are the SAME LENGTH.    Proof !

Are the legs the SAME LENGTH?

Are their slopes PERPINDICULAR?     m1 = slope and the other is  -1/m1

   THAT proves it....

Take the kines you have graphed ....calculate the slope m....and show that no two lines have the same m