Already graphed of course and it forms an isosceles right triangle but once again I don't understand how to prove it
Are the legs the SAME LENGTH?
Are their slopes PERPINDICULAR? m1 = slope and the other is -1/m1
THAT proves it....
Here's the way to prove it, RP
AC and BC are the legs
Show that AC = BC
Then....show that AC is perpendicular to AB
If you need help....let me know