ElectricPavlov

Yes, each has two x intercepts     Function A = 0   at x = - 2  and 1            |x| - 4  = 0   at  x = 4 and -4

https://web2.0calc.com/questions/please-help-meee

https://web2.0calc.com/questions/please-help-meee

Probably....dirt is just really really fine sand.......the dirt particles would have to increase the surface area of the water exposed to air.....Like before....it would be more like adding water TO dirt    rather than adding   dirt TO water....

....something that will increase the surface area       Air bubbling through it......      A giant sponge.......a pile of sand      a pile of rocks.....   More like you would be adding the water TO the substance.....

If your water is in a cone...adding anything that raises the water level will increase evaporation....larger surface area....

    Lots of options for your vague question....

Heat.    Decreased pressure.

Or something that will increase the surface area.....

V =250 (10^(t/93.27) )

or

V = 250 (1.02499^t) 

Set the two functions equal to each other (this is what the questions asks) ...and then solve for 'x'

     Then, plug this value of 'x' back in to one of the equations to find the 'y' value.....

Here is the start.....

x^2-6x+8 = x -2    subtract x from both sides of the equation

x^2 -7x +8 = -2     add 2 to both sides

x^2-7x +10 = 0     Now.....factor ....or use quadratic formula to find the x value(s)

(x-5)(x-2) = 0           You SHOULD be able to find the x values and the coreresponding 'y' values from here....at LEAST ..try ! 

OR:   see:

https://web2.0calc.com/questions/algebra-2_145

Average change =   (change in x) / (change in value af f(x) over same 'x' values)

Ave chg = (9-5)/ (14- -2) =  ???

This question is asking for where is the cos of the angle equao to    - sqr3 / 2

This occurs at   5 pi  /6     and   7pi / 6