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Do you guys actually type all the letters?

So let's assume that Door A is Sports car. Door B and C are toy.

At first time, if you chose door A, and if you switch afterward, you will 100% get toy.

At first time, if you chose door B, and if you switch afterward, you will 100% get sports car.

The same with C, at first time, if you chose door C, and if you switch afterward, you will 100% get sports car.

Therefore if you switch afterward, the probability of getting sports car is $$\frac{2}{3}$$.

If you don't understand, I can explain further.

Ok let me explain. Give me 2 min.

Z and Happy, are you talking about question or egeclaw's comment?

Yeah. The point is, we are trying be the result when someone search math questions.

$$\frac{72}{32}=\frac{9}{4}=2\frac{1}{4}$$

Yes, geno. You are right.

Can you explain?

Egeclaw, this question is very well-known.

And I got this from textbook which is Edexcel AS and A Level Modular Mathematics Statistics 1.

What I'm doing here is just wanna share good questions and have fun.

I should have mentioned it, sorry for that.

Guys, to give you guys hint,

one of two doors is more likely to get sports car.

I know you were just kidding.