Let's first simpify the quadratic. Moving all terms to the left hand side, we get \(2x^2-2x-10=0 \). We want to find the value of \(a+b+6\). Instead of finding the roots of the quadratic, we can use Vieta's Formula. So the sum of the roots would be \(-\left(-\dfrac{2}{2}\right)\). \(1+6=\boxed{7}\). And now we're done! 
Hope this helped!
